Clippers forward Kawhi Leonard has been named the Western Conference’s Player of the Week, according to the NBA (Twitter link), while Bucks forward Giannis Antetokounmpo has won the award in the East.

Los Angeles Clippers forward Kawhi Leonard. Brad Penner-Imagn Images

Leonard helped guide the Clips to a perfect 4-0 week for games played from March 31 through April 6, averaging 24.5 points, 5.8 rebounds, 2.5 assists and 1.8 steals on .513/.381/.857 shooting.

The two-time Finals MVP missed the first 35 games of the season due to a knee injury, but he has rounded into form at a critical time, scoring 20-plus points in each of the past 12 games. Los Angeles is currently the No. 5 seed in a remarkably close West.

Antetokounmpo was spectacular in leading the Bucks to three victories last week (he missed one game, which Milwaukee also won), averaging 36.0 points, 12.3 rebounds, 13.7 assists and 1.7 steals on .638/.500/.838 shooting.

The 30-year-old superstar’s efforts helped the Bucks secure their ninth straight playoff appearance. Milwaukee is currently 44-34, the East’s No. 5 seed.

This is Antetokounmpo’s third Player of the Week in 2024-25 and 26th of his career. It’s the first time Leonard has won the weekly honor this season and 10th time in his career.

Despite averaging 45.0 points, 12.3 rebounds, 10.7 assists and 2.0 steals on .620/.448/.800 shooting in three appearances last week, including a remarkable 61-point triple-double, Nikola Jokic somehow wasn’t nominated for the West’s award, presumably because the Nuggets went 0-4 (he missed one game).

Instead, Leonard beat out Deni Avdija, Stephen Curry, Anthony Edwards, Shai Gilgeous-Alexander, Austin Reaves, Alperen Sengun and teammate Ivica Zubac.

The other nominees in the East were OG Anunoby, Donovan Mitchell, Magic forwards Paolo Banchero and Franz Wagner, Bulls guards Josh Giddey and Coby White, and Pacers teammates Tyrese Haliburton and Myles Turner (Twitter link).